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JEE Mains 05-Sep-2020 Shift 2 Solved Paper
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© examsnet.com
Question : 3
Total: 75
Ten charges are placed on the circumference of a circle of radius
R
with constant angular separation between successive charges. Alternate charges 1,3,5,7,9 have charge
(
+
q
)
each, while 2,4,6,8,10 have charge
(
−
q
)
each. The potential
V
and the electric field
E
at the centre of the circle are respectively:
(Take
V
=
0
at infinity)
V
=
10
q
4
π
∈
0
R
;
E
=
10
q
4
π
∈
0
R
2
V
=
0
;
E
=
10
q
4
π
∈
0
R
2
V
=
0
;
E
=
0
V
=
10
q
4
π
∈
0
R
;
E
=
0
Validate
Solution:
Potential of centre
=
V
=
∑
(
k
q
R
)
V
C
=
K
(
∑
q
)
R
V
C
=
K
(
0
)
R
=
0
Electric field at centre
→
E
B
=
∑
→
E
Let
mathrm
E
be electric field produced by each charge at the centre, then resultant electric field will be
E
C
=
0
,
since equal electric field vectors are acting at equal angle so their resultant is equal to zero.
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