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JEE Mains 05-Sep-2020 Shift 2 Solved Paper
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© examsnet.com
Question : 49
Total: 75
The volume, in
m
L
,
of
0.02
M
K
2
C
r
2
O
7
solutionrequired to react with 0.288 g of ferrous oxalate in acidic medium is ______.
(Molar mass of
F
e
=
56
g
m
o
l
−
1
)
Your Answer:
Validate
Solution:
K
2
C
r
2
O
7
n
=
6
+
F
e
C
2
O
4
n
=
3
─
─
─
▸
C
r
+
3
+
F
e
+
3
+
C
O
2
0.02
×
6
×
V
(
m
L
)
1000
=
0.288
144
×
3
⇒
V
=
50
ML
© examsnet.com
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