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JEE Mains 05-Sep-2020 Shift 2 Solved Paper
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© examsnet.com
Question : 7
Total: 75
Two coherent sources of sound,
S
1
and
S
2
, produce sound waves of the same wavelength,
λ
=
1
m
,
in phase.
S
1
and
S
2
are placed
1.5
m
apart (see fig.) A listener, located at L, directly in front of
S
2
finds that the intensity is at a minimum when he is
2
m
away from
S
2
. The listener moves away from
S
1
, keeping his distance from
S
2
fixed. The adjacent maximum of intensity is observed when the listener is at a distance
d
from
S
1
.
Then,
d
is :
12
m
3
m
5
m
2
m
Validate
Solution:
Initially
S
2
L
=
2
m
S
1
L
=
√
2
2
+
(
3
2
)
2
S
1
L
=
5
2
=
2.5
m
Δ
x
=
+
S
1
L
−
S
2
L
=
0.5
m
So since
λ
=
1
m
∴
Δ
x
=
λ
2
So while listener moves away from
S
1
Then,
Δ
x
(
=
S
1
L
−
S
2
L
)
increases
and hence, at
Δ
x
=
λ
first maxima will appear.
Δ
x
=
λ
=
S
1
L
−
S
2
L
1
=
d
−
2
⇒
d
=
3
m
© examsnet.com
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