Arrange the following solutions is the decreasing order of {pOH} : (A) 0.01 M {HCl} (B) 0.01 M {NaOH} (C) 0.01 M {CH}₃{COONa} (D) 0.01\,{M}\,{NaCl} [6 Sep 2020 Shift 1]

Correct Answer is : (A)>(D)>(Q)>(B)(A) > (D) > (Q) > (B)(A)>(D)>(Q)>(B)

Correct Answer is : (A)>(D)>(Q)>(B)(A) > (D) > (Q) > (B)(A)>(D)>(Q)>(B)

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JEE Mains 06 Sep 2020 Shift 1 Solved Paper

Section: Chemistry

Question : 12 of 75

Marks: +1, -0

\mathrm{pOH}

\mathrm{HCl}

\mathrm{NaOH}

\mathrm{CH}_3\mathrm{COONa}

0.01\,\mathrm{M}\,\mathrm{NaCl}

Solution:

(A)

10^{-2}\,\mathrm{M}\,\mathrm{HCl} \Rightarrow [\mathrm{H}^{+}] = 10^{-2}\,\mathrm{M} \Rightarrow \mathrm{pH} = 2 \Rightarrow \mathrm{pOH} = 14-2 = 12

(B)

10^{-2}\,\mathrm{M}\,\mathrm{NaOH} \Rightarrow [\mathrm{OH}^{-}] = 10^{-2}\,\mathrm{M} \Rightarrow \mathrm{pOH} = 2

(C)

10^{-2}\,\mathrm{M}\,\mathrm{CH}_3\mathrm{COO}^{-}\mathrm{Na}^{+} \Rightarrow [\mathrm{OH}^{+}] > 10^{-7} \Rightarrow \mathrm{pOH} < 7

(D)

10^{-2}\,\mathrm{M}\,\mathrm{NaCl} \Rightarrow

Neutral

\mathrm{pOH} = 7

Order of

\mathrm{pOH}

value

A > D > C > B

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