A solution of two components containing {n}_{1} moles of the 1^{{\st }} component and {n}_{2} moles of the 2^{{
d }} component is prepared. {\M}_{1} and {\M}_{2} are the molecular weights of component 1 and 2 respectively. If {d} is the density of the solution in {\g} {\mL}^{-1}, {\C}_{2} is the molarity and {x}_{2} is the mole fraction of the 2^{ {
d }} component, then {\C}_{2} can be expressed as :
[6 Sep 2020 Shift 1]

Question

Examsnet · Accepted Answer

Correct Answer is : C2=1000dx2M1+x2(M2−M1)

JEE Mains 06-Sep-2020 Shift 1 Solved Paper