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JEE Mains 2020 Model Paper 1 New Pattern
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© examsnet.com
Question : 3
Total: 75
A boy 1.5m tall is standing t some distance a 30m tall building. The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building. The distance he walked towards the building is
10
√
3
19
√
3
30
√
3
30
Validate
Solution:
From ΔBFE, cot 60° =
E
F
28.5
, EF =
28.5
√
3
From ΔBDE , cot 30° =
B
E
28.5
, BE =
28
√
3
BF = BE - EF =
28.5
√
3
−
28.5
√
3
=
28.5
(
√
3
−
1
√
3
)
=
28.5
(
2
√
3
)
=
57
√
3
=
19
√
3
© examsnet.com
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