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JEE Mains 2020 Model Paper 2 New Pattern

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Question : 17

Total: 75

AB is a focal chord of x2−2x+y−2 = 0 whose focus is S. If AS = µ then BS is equal to

4µ
4µ−1
µ
4µ−1
2µ
4µ−1
None of these

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