Horizontal and vertical components of initial velocity are: ux=20√2‌cos‌45°=20m∕s And uy=20√2‌sin‌45°=20m∕s After 1 s horizontal component remains unchanged while the vertical component becomes vy=uy−gt=20−10×1=10m∕s Due to explosion one part comes to rest. Hence, from conservation of linear momentum vertical component of second part will become v′y=20m∕s. Therefore, maximum height attained by the second part will be H=h1+h2 Here, h1 = height attained in 1 s =20×1−
