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Test Index
JEE Mains 26 July 2022 Shift 2 Paper
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Section:
Physics
Share question:
© examsnet.com
Question : 32 of 90
Marks:
+1
,
-0
In a Vernier Calipers, 10 divisions of Vernier scale is equal to the 9 divisions of main scale. When both jaws of Vernier calipers touch each other, the zero of the Vernier scale is shifted to the left of zero of the main scale and
4
  
th
  
4^{\;\text{th}\;}
4
th
Vernier scale division exactly coincides with the main scale reading. One main scale division is equal to
1
 mm
1\ \text{mm}
1
Â
mm
. While measuring diameter of a spherical body, the body is held between two jaws. It is now observed that zero of the Vernier scale lies between 30 and 31 divisions of main scale reading and
6
  
th
  
6^{\;\text{th}\;}
6
th
Vernier scale division exactly coincides with the main scale reading. The diameter of the spherical body will be :
[26-Jul-2022-Shift-2]
3.02
 cm
3.02\ \text{cm}
3.02
Â
cm
3.06
 cm
3.06\ \text{cm}
3.06
Â
cm
3.10
 cm
3.10\ \text{cm}
3.10
Â
cm
3.20
 cm
3.20\ \text{cm}
3.20
Â
cm
Validate
Solution:
  
 1 M.S.DÂ
  
=
1
 mm
\;\text{ 1 M.S.D }\;=1\ \text{mm}
 1 M.S.DÂ
=
1
Â
mm
  
 9 M.S.DÂ
  
=
10
 V.S.D
\;\text{ 9 M.S.D }\;=10\ \text{V.S.D}
 9 M.S.DÂ
=
10
Â
V.S.D
  
 1 V.S.DÂ
  
=
0.9
  
 M.S.DÂ
  
=
0.9
 mm
\;\text{ 1 V.S.D }\;=0.9\;\text{ M.S.D }\;=0.9\ \text{mm}
 1 V.S.DÂ
=
0.9
 M.S.DÂ
=
0.9
Â
mm
  
 L.C of vernier caliperÂ
  
=
1
−
0.9
=
0.1
 mm
=
0.01
 cm
\;\text{ L.C of vernier caliper }\;=1-0.9=0.1\ \text{mm}=0.01\ \text{cm}
 L.C of vernier caliperÂ
=
1
−
0.9
=
0.1
Â
mm
=
0.01
Â
cm
  
 zero errorÂ
  
=
(
10
−
4
)
×
0.1
 mm
=
−
0.6
 mm
\;\text{ zero error }\;=(10-4)\times 0.1\ \text{mm}=-0.6\ \text{mm}
 zero errorÂ
=
(
10
−
4
)
×
0.1
Â
mm
=
−
0.6
Â
mm
  
 ReadingÂ
  
=
  
 M.S.RÂ
  
+
  
 V.S.RÂ
  
−
  
 Zero errorÂ
  
\;\text{ Reading }\;=\;\text{ M.S.R }\;+\;\text{ V.S.R }\;-\;\text{ Zero error }\;
 ReadingÂ
=
 M.S.RÂ
+
 V.S.RÂ
−
 Zero errorÂ
=
3
 cm
+
6
×
0.01
−
[
−
0.06
]
=3\ \text{cm}+6\times 0.01-[-0.06]
=
3
Â
cm
+
6
×
0.01
−
[
−
0.06
]
=
3
+
0.06
+
0.06
=3+0.06+0.06
=
3
+
0.06
+
0.06
=
3.12
 cm
=3.12\ \text{cm}
=
3.12
Â
cm
Nearest given answer in the options is
3.10
3.10
3.10
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