Statement 2 is true and A (0,0) is equidistant from the vertices of
ΔPQR ∴ (0,0) is circum centre of ΔPQR
Also, given orthocenter = (0,0)
⇒ ortho centre = circumcentre
⇒ ΔPQR is equilateral
∴ Centroid of ΔPQR = (0, 0)
⇒ cosα + cosβ +cosγ = 0 ,
and sinα + sinβ + sinγ = 0
⇒Σ cos (α - β) = -