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JEE Mains Model Paper 2
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© examsnet.com
Question : 36
Total: 90
At what temperature will the rms speed of oxygen molecule will be sufficient for escapingfrom the earth ?
[
v
e
= 11.2 km/s , m = 2.76 ×
10
−
26
Kg and k = 1.38 ×
10
−
23
J/K]
T < 8.36 ×
10
4
K
T < 1.36 ×
10
4
K
T > 1.36 ×
10
4
K
T > 8.36 ×
10
4
K
Validate
Solution:
If the temperature is T, according to kinetic theory of gases translational KE =
3
2
KT
The oxygen molecule will escape from earth if
3
2
KT >
1
2
m
v
e
2
i.e. T >
m
v
e
2
3
K
i.e. T >
2.76
×
10
−
26
×
(
11.2
×
10
3
)
2
3
×
1.39
×
10
−
23
i.e. T > 8.36 ×
10
4
K
© examsnet.com
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