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JEE Mains Model Paper 25
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© examsnet.com
Question : 4
Total: 90
For 1/m of the distance between two stations a train is uniformly accelerated and 1/n of thedistance it is uniformly retarded and rest with uniform motion. It starts from rest at one stationand comes to rest at the other. The ratio of the greatest velocity to the average velocity will be
1 +
1
m
+
1
n
1 +
1
m
-
1
n
1
m
+
1
n
- 1
1
m
+
1
n
Validate
Solution:
Avg vel × time = S ;
V
2
t
1
=
x
m
;
V
t
1
=
2
x
m
V
2
t
3
=
x
n
;
V
t
3
=
2
x
n
;
V
t
2
= x -
x
m
−
x
n
; V
(
t
1
+
t
2
+
t
3
)
= x
(
1
+
1
m
+
1
n
)
V
max
V
=
V
x
∕
(
t
1
+
t
2
+
t
3
)
= 1 +
1
m
+
1
n
© examsnet.com
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