Dimension of h [h] = [ML2T−1] [G] = [M−1L3T2−] [c] = [LT−1] For mass, let m = cahbGc ⇒ [ML0T0] = [LT−1]a[ML2T1−]b[M−1L3T−2]c b - 2 = 1 , a + 2b + 3c = 0 , -a -b - 2c = 0 ⇒ a = -1/2 , b = 1/2 , c = 1/2 c1∕2h1∕2G−1∕2 ⇒ m = √