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JIPMER 2018 Evening Paper
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© examsnet.com
Question : 29
Total: 98
Oxidation number of Cr in
[
C
r
[
N
H
3
]
4
C
l
2
]
+
+4
+2
+3
+6
Validate
Solution:
(3)
Oxidation number of Cr in
[
C
r
[
N
H
3
]
4
C
l
2
]
+
is +3
x + (4×0) + (-1×2) = +1
x - 2 = +1
x = +3
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