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JIPMER 2018 Evening Paper
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© examsnet.com
Question : 54
Total: 98
For maximum range, the angle of projection should be
0º
45º
30º
60º
Validate
Solution:
(2)
R =
u
2
sin
(
2
θ
)
g
For maximum range 2θ = 90º
θ = 45º
© examsnet.com
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