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JIPMER 2019 Evening Papers Online Practice
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© examsnet.com
Question : 50
Total: 103
Maximum acceleration in SHM –
ω
2
A
ω
2
A
2
ω
2
A
2
0
Validate
Solution:
(1)
Acceleration in SHM is given as.
a = –
ω
2
x
x = distance from mean position
x
m
a
x
= A; A = amplitude
a
m
a
x
=
ω
2
A
© examsnet.com
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