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KCET 2011 Math Solved Paper

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Question : 34

Total: 60

The equation of a hyperbola whose asymptotes are 3x±5y=0 and vertices are (±5,0) is ...................

3x2−5y2=25
5x2−3y2=225
25x2−9y2=225
9x2−25y2=225

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