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KCET 2014 Chemistry Solved Paper
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© examsnet.com
Question : 3
Total: 60
For the equilibrium :
C
a
C
O
3
(
s
)
⇌
C
a
O
(
s
)
+
C
O
2
(
g
)
;
K
p
=
1.64
atm
at 1000 K
50 g of
C
a
C
O
3
in a 10 litre closed vessel is heated to 1000 K. Percentage of
C
a
C
O
3
that remains unreacted at equilibrium is
(Given R = 0.082 L
atm
K
−
1
mol
−
1
)
50
20
40
60
Validate
Solution:
C
a
C
O
3
(
s
)
⇌
C
a
O
(
s
)
+
C
O
2
(
g
)
;
K
p
=
1.64
Number of moles of
C
a
C
O
3
=
50
100
=
0.5
mol
K
p
=
P
CO
3
From the ideal gas equation
pV = nRT
1.64
×
10
=
n
×
0.085
×
100
n
=
0.2
Therefore, no. of moles of
C
O
2
formed
=
0.2
mol
No. of moles of unreacted
C
a
C
O
3
left
=
0.5
–
0.2
=
0.3
mol
Percentage of unreacted
C
a
C
O
3
=
0.3
0.5
×
100
=
60
%
© examsnet.com
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