Given that,3x−2=4y−3=5z−4 → (1) So, direction ratio’s of line are 3, 4, 5. Since, line and plane are parallel. So, normal to plane and line are perpendicular Now, a1a2+b1b2+c1c2=0 for plane 2x+y−2z=0 Now, 3(2)+4(1)−2(5)=0 Hence, required equation is 2x+y−2z=0