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KCET 2014 Physics Solved Paper
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© examsnet.com
Question : 14
Total: 60
A rotating wheel changes angular speed from 1800 rpm to 3000 rpm in 20 s. What is the angular acceleration assuming to be uniform ?
60
π
rad
s
−
2
90
π
rad
s
−
2
2
π
rad
s
−
2
40
π
rad
s
−
2
Validate
Solution:
For angular speed of 1800 rpm
ω
1
=
2
π
f
1
=
2
π
(
1800
60
)
=
60
π
rad
s
−
1
For angular speed of 3000 rpm
ω
2
=
2
π
f
2
=
2
π
(
3000
60
)
=
100
π
rad
s
−
1
Therefore, angular acceleration
=
ω
2
−
ω
1
t
=
100
π
−
60
π
20
=
40
π
20
=
2
π
Thus, angular acceleration of rotating wheel
=
2
π
rads
−
2
© examsnet.com
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