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KCET 2015 Biology Solved Paper
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© examsnet.com
Question : 36
Total: 60
In a 3.2 kbp long piece of DNA, 820 adenine bases were found.
What would be the number of cytosine bases?
1560
1480
780
740
Validate
Solution:
Total DNA = 3.2 kbp = 3200 bp
Adenine = 820
According to Chargaff’s rule [A] = [T], [G] = [C]
So, Thymine 820
Therefore, total AT content
=
820
+
820
=
1640
GC content
=
3200
–
1640
=
1560
so, cytosine
=
1560
/
2
=
780
.
© examsnet.com
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