Test Index

KCET 2015 Math Solved Paper

Question : 21 of 60

Marks: +1, -0

y = x^2 - \frac{1}{x^2}

at (-1, 0) is

Solution:

Given equation of curve,

y=x^{2}-\frac{1}{x^{2}}

\Rightarrow y=x^{2}-x^{-2}

Differentiating both the sides, we get

y'=2x-(-2)x^{-3}=2x+\frac{2}{x^{3}}

(-1,0)

, we get

m_{1}=-2-2=-4

So, slope of the curve is −4

We know that, slopes of two perpendicular lines is given by

m_{1} m_{2}=-1

\Rightarrow m_{2}=\frac{1}{4}

Hence, the slope of the normal to the curve is

\frac{1}{4}

Go to Question:

Prev Question

Next Question