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KCET 2015 Physics Solved Paper
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Question : 14
Total: 60
When two tuning forks A and B are sounded together. 4 beats per second are heard. The frequency of the fork B is 384 Hz. When one of the prongs of the fork A is filed and sounded with B, the beat frequency increases, then the frequency of the fork A is
380 Hz
388 Hz
379 Hz
389 Hz
Validate
Solution:
Given, beat frequency = 4 beats per second; frequency of fork B = 384 Hz
Now, we know beat frequency
f
A
−
f
B
Here
f
A
is frequency of fork A;
f
B
is frequency of fork B
⇒
4
=
f
A
−
384
⇒
f
A
=
4
+
384
=
388
Therefore, frequency of the fork A is 388 Hz.
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