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KCET 2015 Physics Solved Paper
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© examsnet.com
Question : 37
Total: 60
An aircraft with a wingspan of 40 m flies with a speed of
1080
k
m
h
−
1
in the eastward direction at a constant altitude in the northern hemisphere, where the vertical component of the earth’s magnetic field
1.75
×
10
−
5
T. Then the emf developed between the tips of the wings is
0.5 V
0.34 V
0.21V
2.1V
Validate
Solution:
Given, length of wing,
l
=
40
m
;
s
p
e
e
d
,
v
=
1080
kmh
−
1
=
1080
×
5
18
m
s
−
1
Earth’s magnetic field,
B
=
1.75
×
10
−
5
T
Then emf
E
=
B
l
v
=
(
1.75
×
10
−
5
)
×
40
×
1080
×
5
18
=
21000
×
10
−
5
=
0.21
V
Therefore, the emf developed between the tips of the wing is 0.21 V
© examsnet.com
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