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KCET 2015 Physics Solved Paper
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© examsnet.com
Question : 50
Total: 60
If an electron in hydrogen atom jumps from an orbit of level n = 3 to an orbit of level n = 2. the emitted radiation has a frequency (R = Rydberg constant, C = velocity of light)
3
R
C
27
R
C
25
8
R
C
9
5
R
C
36
Validate
Solution:
We know that
1
λ
=
R
(
1
n
1
2
−
1
n
2
2
)
Using
λ
f
=
c
⇒
1
λ
=
f
c
f
c
=
R
(
1
n
1
2
−
1
n
2
2
)
⇒
f
=
R
c
(
1
n
1
2
−
1
n
2
2
)
Given
n
1
=
2
;
n
2
=
3
⇒
f
=
R
c
(
1
2
2
−
1
3
2
)
=
R
c
(
1
4
−
1
9
)
=
R
c
(
9
−
4
)
4
×
9
=
5
R
c
36
Therefore, frequency of emitted radiation is
5
36
Rc
© examsnet.com
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