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KCET 2016 Chemistry Solved Paper
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© examsnet.com
Question : 49
Total: 60
The increasing order of bond order of
O
2
,
O
2
+
,
O
2
−
,
and
O
2
−
−
is
O
2
+
,
O
2
,
O
2
−
,
O
2
2
−
O
2
2
−
,
O
2
−
,
O
2
+
,
O
2
O
2
,
O
2
+
,
O
2
−
,
O
2
2
−
O
2
2
−
,
O
2
−
,
O
2
,
O
2
+
Validate
Solution:
Electronic configuration of
O
2
:
σ
1
s
2
σ
*
1
s
2
σ
2
s
2
σ
*
2
s
2
σ
2
p
z
2
π
2
p
x
2
=
π
2
p
y
2
π
*
2
p
x
1
=
π
*
2
p
y
1
Bond order
=
[
No. of bonding
e
−
s
−
No. of anti-bonding
e
−
s
]
2
O
2
=
1
2
(
10
−
6
)
=
2
O
2
−
=
1
2
(
10
−
7
)
=
1.5
O
2
2
−
=
1
2
(
10
−
8
)
=
1
O
2
+
=
1
2
(
10
−
5
)
=
5
2
=
2.5
Therefore, the correct decreasing order of bond order is
O
2
+
>
O
2
>
O
2
−
>
O
2
2
−
.
© examsnet.com
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