Given line,y=3x−1 →(1) General equation of line is given by y=mx+c Here m = 3 and c = –1. Condition for two perpendicular lines is m1⋅m2=−1 So, 3m2=−1⇒m2=−
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Standard equation of line passing through point (x1,y1) is given by (y−y1)=m(x−x1) Here (x1,y1)=(1,2).So, (y−2)=−