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KCET 2017 Physics Solved Paper
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© examsnet.com
Question : 2
Total: 60
A car moving with a velocity of 20 m
s
−
1
is stopped in a distance of 40 m. If the same car is travelling at double the velocity, the distance travelled by it for same retardation is
640 m
320 m
1280 m
160 m
Validate
Solution:
Given, velocity of car
=
20
m
s
−
1
; distance = 40 m
We know, distance travelled
=
(
velocity
)
2
2
×
acceleration
⇒ acceleration
=
(
velocity
)
2
distance travelled
=
(
20
)
2
40
=
400
40
=
10
m
s
−
2
Therefore, acceleration
=
10
m
s
−
2
When Velocity
=
2
×
20
=
40
m
s
−
1
then, distance travelled
=
(
40
)
2
10
=
1600
10
=
160
m
Thus, distance travelled by car = 160 m
© examsnet.com
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