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KCET 2017 Physics Solved Paper
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© examsnet.com
Question : 47
Total: 60
In a system of two crossed polarisers, it is found that the intensity of light from the second polariser is half from that of first polariser. The angle between their pass axes is
45°
60°
30°
0°
Validate
Solution:
By Malus Law, we have
I
=
I
0
cos
θ
Given, intensity of light from second polariser is half of that from the first polariser, so
⇒
I
0
2
=
I
0
cos
2
θ
⇒
cos
2
θ
=
1
2
⇒
cos
θ
=
1
√
2
⇒
θ
=
cos
−
1
(
1
√
2
)
⇒
θ
=
45
°
Therefore, angle between the pass axes of polarisers is 45°.
© examsnet.com
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