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KCET 2017 Physics Solved Paper
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© examsnet.com
Question : 8
Total: 60
The value of acceleration due to gravity at adepth of 1600 km is equal to:
[Radius of earth = 6400 km]
9.8 m
s
−
2
4.9 m
s
−
2
19.6 m
s
−
2
7.35 m
s
−
2
Validate
Solution:
Acceleration due to gravity at a depth d and radius R isgiven as
g
′
=
g
[
1
−
d
R
]
=
g
(
1
−
1600
6400
)
=
g
(
1
−
1
4
)
=
g
×
3
4
⇒
g
′
=
9.8
×
3
4
=
7.35
m
s
−
2
Therefore, the acceleration due to gravity at a depth of 1600 km is equal to
7.35
m
s
−
2
© examsnet.com
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