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KCET 2021 Physics Solved Paper
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© examsnet.com
Question : 36
Total: 60
Two capillary tubes P and Q are dipped vertically in water. The height of water level in capillary tube P is
2
3
of the height in capillary tube Q. The ratio of their diameter is
2
:
3
3
:
2
3
:
4
4
:
3
Validate
Solution:
As we know, height of capillary rise or fall of a liquid in a capillary tube is given as
h
=
2
T
cos
θ
r
ρ
g
⇒
h
∝
1
r
...(ii)
where,
r
is the radius of the capillary lube.
Given, height of water level in capillary tube
P
=
2
3
height of water in capillary tube Q.
⇒
h
P
=
2
3
h
Q
or
h
P
h
Q
=
2
3
From Eq. (i), we can write
h
p
h
Q
=
r
Q
r
p
⇒
2
3
=
r
Q
r
P
or
r
P
:
r
Q
=
3
:
2
As diameter of the tube is equals to twice the radius.
So,
(
diameter
)
P
(
diameter
)
Q
=
3
2
© examsnet.com
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