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KCET 2022 Chemistry Solved Paper
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© examsnet.com
Question : 60
Total: 60
If
3
g
of glucose (molar mass
=
180
g
) is dissolved in
60
g
of water at
15
∘
C
, the osmotic pressure of the solution will be
6.57
atm
5.57
atm
0.34
atm
0.65
atm
Validate
Solution:
π
=
C
⋅
R
⋅
T
=
w
2
M
2
1000
V
(
m
ℓ
)
×
R
⋅
T
⇒
3
180
×
1000
60
×
0.0821
×
288
=
6.568
atm
© examsnet.com
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