When light passes into a non-reflecting, non-absorbing medium, no energy is lost at the boundary. In particular:Energy flux is given by the (time-averaged) Poynting vectorS=E×HFor no reflection and no absorption, the tangential components of both fields are continuous across the interface: E1=E2,H1=H2.Hence the incident and transmitted fluxes are equal:S1=E1H1=E2H2=S2Since all the energy that arrives is carried forward, the total energy carried by the wave remains the same.Answer: Option A (remains same).