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KEAM 2010 Math Paper
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© examsnet.com
Question : 4
Total: 120
The distance between the foci of the conic
7
x
2
−
9
y
2
=
63
is equal to
8
4
3
7
12
Validate
Solution:
Equation of the given conic is
7
x
2
−
9
y
2
=
63
It can be rewritten as
x
2
9
−
y
2
7
=
1
which is an equation of hyperbola Comparing the above equation with standard equation of hyperbola
x
2
a
2
−
y
2
b
2
=
1
, we get
a
2
=
9
,
b
2
=
7
⟹
a
=
3
,
b
=
√
7
Now, Distance between foci is
2
a
e
=
2
a
√
a
2
+
b
2
a
2
=
2
√
9
+
7
=
2
×
4
=
8
© examsnet.com
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