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KEAM 2010 Physics and Chemistry Paper
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© examsnet.com
Question : 3
Total: 119
In the circuit shown, the current through the
5
Ω
resistor is
8
3
A
9
13
A
4
13
A
1
3
A
2
3
A
Validate
Solution:
1
R
=
1
2
+
1
2
=
1
R
=
1
Ω
Total resistance
=
R
+
5
=
1
+
5
=
6
Ω
E
eff
=
E
1
r
1
+
E
2
r
2
r
1
+
r
2
=
2
×
2
+
2
×
2
2
+
2
=
2
V
i
=
E
eff
R
=
2
6
=
1
3
A
© examsnet.com
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