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KEAM 2011 Math Paper
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© examsnet.com
Question : 12
Total: 120
The equation of one of the diameters of the circle
x
2
−
y
2
−
6
x
+
2
y
=
0
is
x
−
3
y
=
0
x
+
3
y
=
0
3
x
+
y
=
0
3
x
−
y
=
0
x
+
2
y
=
0
Validate
Solution:
The equation of circle is
x
2
−
y
2
−
6
x
+
2
y
=
0
centre
=
(
3
−
1
)
since, the equation of diameter passes through the centre of the circle, then the coordinates of centre will satisfy the equation of diameter. From option, only the equation is
x
−
3
y
=
0
.
© examsnet.com
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