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KEAM 2011 Math Paper

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Question : 15 of 120

Marks: +1, -0

The equation of the latus rectum of the conic

y^2=\frac{5}{2}x

is

$8x-5=0$
$8x+5=0$
$5x+8=0$
$x-5=0$
$x-8=0$

Solution:

Given equation of conic,

y^{2}=\;\frac{5x}{2}

the length of focal

\Rightarrow \; \frac{5}{8}

\left(\because 4a=\frac{5}{2}\right)

\Rightarrow \;\; x=\;\frac{5}{8}

So, equation of latusrectum is,

8x-5=0

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