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KEAM 2012 Math Paper
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© examsnet.com
Question : 8
Total: 120
∫
e
x
x
(
x
log
x
+
1
)
dx
is equal to
e
x
x
+
C
x
e
x
log
|
x
|
+
C
e
x
log
|
x
|
+
C
x
(
e
x
+
log
|
x
|
)
+
C
x
e
x
+
log
|
x
|
+
C
Validate
Solution:
∫
e
x
x
(
x
log
x
+
1
)
d
x
=
∫
e
x
II
log
x
I
d
x
+
∫
e
x
x
d
x
=
e
x
log
x
−
∫
e
x
x
d
x
+
∫
e
x
x
d
x
+
C
=
e
x
log
x
+
C
© examsnet.com
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