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KEAM 2012 Physics and Chemistry Paper
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© examsnet.com
Question : 44
Total: 120
1 cc of water becomes 1681 cc of steam when boiled at a pressure of
10
5
N
m
−
2
.
The. increasing internal energy of the system is
(L.T. of steam is 540 cal
g
−
1
, 1 calorie = 4.2 J)
300 cal
500 cal
225 cal
600 cal .
1000 cal
Validate
Solution:
Initial volume of water
=
V
1
=
1
c
m
3
Volume of steam
=
V
2
=
1681
c
m
3
Change in volume
d
V
=
V
2
−
V
1
=
1681
=
1680
c
m
3
=
1680
×
10
−
6
m
3
Pressure
p
=
10
5
N
/
m
2
d
Q
=
m
L
=
1
×
540
×
4.2
=
22.68
J
d
W
=
p
d
V
=
10
5
×
1680
×
10
−
6
=
168
Internal energy
d
U
=
2268
−
168
=
2100
J
=
500
cal
© examsnet.com
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