Given, roots of the equation x2+px+c=0 are 2 and −2 ∴‌‌−p=2−2⇒p=0 and (2)⋅(−2)=c⇒c=−4 Again, roots of the equation x2+bx+q=0 are −1 and −2 ∴‌‌−b=−1−2⇒b=3 and (−1)⋅(−2)=q⇒q=2 ∴‌‌x2+bx+c≡x3+3x−4=0 ⇒‌‌(x−1)(x+4)=0 So, the required roots are 1 and −4 .