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KEAM 2013 Math Paper
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© examsnet.com
Question : 45
Total: 120
t
a
n
(
3
t
a
n
−
1
(
1
5
)
−
π
4
)
=
−
13
46
−
11
46
−
7
46
−
4
23
−
9
46
Validate
Solution:
tan
{
3
tan
−
1
(
1
5
)
−
π
4
}
=
tan
{
2
tan
−
1
(
1
5
)
+
tan
−
1
(
1
5
)
−
tan
−
1
(
1
)
}
=
tan
{
tan
−
1
(
2
×
1
5
1
−
1
25
)
+
tan
−
1
(
1
5
−
1
1
+
1
5
)
]
}
=
tan
{
tan
−
1
(
2
5
×
25
24
)
+
tan
−
1
(
−
4
5
×
5
6
)
}
=
tan
{
tan
−
1
(
5
12
)
−
tan
−
1
(
2
3
)
}
tan
(
tan
−
1
5
12
−
2
3
1
+
5
18
)
=
tan
{
tan
−
1
(
−
3
12
×
18
23
)
}
=
−
9
46
© examsnet.com
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