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KEAM 2013 Math Paper
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© examsnet.com
Question : 95
Total: 120
If
y
=
1
1
+
x
+
x
2
,
then
d
y
d
x
is equal to
y
2
(
1
+
2
x
)
−
(
1
+
2
x
)
y
2
y
(
1
+
2
x
)
−
y
(
1
+
2
x
)
−
y
2
(
1
+
2
x
)
Validate
Solution:
Given,
y
=
1
1
+
x
+
x
2
⇒
1
+
x
+
x
2
=
1
y
On differentiating w.r.t.
x
, we get
0
+
1
+
2
x
=
−
1
y
2
d
y
d
x
⇒
d
y
d
x
=
−
(
1
+
2
x
)
y
2
© examsnet.com
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