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KEAM 2013 Physics and Chemistry Paper
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© examsnet.com
Question : 10
Total: 120
A particle tied to a string describes a vertical circular motion of radius continually. If it has a velocity
√
3
g
r
at the highest point, then the ratio of the respective tensions in the string holding it at the highest and lowest points is
4 : 3
5 : 4
1 : 4
3 : 2
1 : 2
Validate
Solution:
Tension at highest point
T
H
=
m
v
2
r
−
m
g
=
3
m
g
−
m
g
=
2
m
g
and tension at lowest point
T
L
=
m
v
2
r
+
m
g
Here,
v
L
2
=
3
g
r
+
2
g
⋅
2
t
=
7
g
r
So
T
L
=
7
m
g
+
m
g
=
8
m
g
Hence,
T
H
T
L
=
2
m
g
8
m
g
=
1
4
© examsnet.com
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