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KEAM 2015 Math Paper
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© examsnet.com
Question : 107
Total: 120
A function
f
satisfies the relation
f
(
n
2
)
=
f
(
n
)
+
6
for
n
≥
2
and
f
(
2
)
=
8.
Then the value of
f
(
256
)
is
24
26
22
28
32
Validate
Solution:
Given that,
f
(
n
2
)
=
f
(
n
)
+
6
On putting
n
=
2
,
we get
f
(
4
)
=
f
(
2
2
)
=
f
(
2
)
+
6
=
8
+
6
=
14
[
∵
f
(
2
)
=
8
]
On putting
n
=
4
,
we get
f
(
16
)
=
f
(
4
2
)
=
f
(
4
)
+
6
=
14
+
6
=
20
On putting
n
=
16
,
we get
f
(
256
)
=
f
(
16
2
)
=
f
(
16
)
+
6
=
20
+
6
=
26
© examsnet.com
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