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KEAM 2015 Math Paper
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© examsnet.com
Question : 5
Total: 120
If
s
=
2
t
3
−
6
t
2
+
a
t
+
5
is the distance travelled by a particle at time t and if the velocity is - 3 when its acceleration is zero, then the value of a is
-3
3
4
-4
2
Validate
Solution:
Given,
s
=
2
t
3
−
6
t
2
+
a
t
+
5
Velocity,
V
=
d
s
d
t
=
6
t
2
−
12
t
+
a
Acceleration,
A
=
d
2
S
d
t
2
=
12
t
−
12
since,
A
=
0
⇒
12
t
−
12
=
0
⇒
t
=
1
A
t
t
=
1
V
=
6
−
12
+
a
=
a
−
6
It is given that, at
A
=
0
,
V
=
−
3
⇒
a
−
6
=
−
3
⇒
a
=
3
© examsnet.com
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