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KEAM 2015 Math Paper
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© examsnet.com
Question : 58
Total: 120
The area and perimeter of a rectangle are A and P respectively. Then P and A satisfy the inequality
P
+
A
>
P
A
P
2
≤
A
A
−
P
<
2
P
2
≤
4
A
P
2
≥
16
A
Validate
Solution:
Let area and perimeter of a rectangle of sides
x
and
y
be
A
and
P
∴
A
=
x
y
,
P
=
2
(
x
+
y
)
since,
(
x
+
y
)
2
≥
4
×
y
⇒
(
P
2
)
2
≥
4
A
⇒
P
2
≥
16
A
© examsnet.com
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