Given, P=400µC=400×10−6C E=50Vm−1 θ=30∘ We know that, torque acting on an electric dipole,τ=PE‌sin‌θ where, P= dipole moment =400×10−6×50×sin‌30∘ =400×10−6×50×‌
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=200×50×10−6=10−2N−m This torque will act normal to both E and µ.