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KEAM 2017 Math Paper
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© examsnet.com
Question : 117
Total: 120
lim
x
→
0
√
2
+
x
−
√
2
−
x
x
is equal to
1
√
2
√
2
0
Does not exist
1
2
√
2
Validate
Solution:
We have
lim
x
→
0
√
2
+
x
−
√
2
−
x
x
=
lim
x
→
0
√
2
+
x
−
√
2
−
x
x
×
√
2
+
x
+
√
2
−
x
√
2
+
x
+
√
2
−
x
=
lim
x
→
0
(
2
+
x
)
−
(
2
−
x
)
x
[
√
2
+
x
+
√
2
−
x
]
=
lim
x
→
0
2
x
x
√
2
+
x
+
√
2
−
x
=
lim
x
→
0
2
√
2
+
x
+
√
2
−
x
=
2
√
2
+
0
+
√
2
−
0
=
2
2
√
2
=
1
√
2
© examsnet.com
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