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KEAM 2017 Math Paper
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© examsnet.com
Question : 14
Total: 120
The area bounded by the curves
y
=
–
x
2
+
3
and y = 0 is
√
3
+
1
√
3
4
√
3
5
√
3
6
√
3
Validate
Solution:
We have
y
=
−
x
2
+
3
⇒
x
2
=
−
(
y
−
3
)
The above curve intersect
X
-axis at the points where
y
=
0
∴
x
2
=
3
⇒
x
=
±
√
3
∴
Point of intersection with
X
-axis are
(
±
√
3
,
0
)
∴
Required area
=
2
∫
0
√
3
y
d
x
=
2
∫
0
√
3
(
−
x
2
+
3
)
d
x
=
2
[
−
x
3
3
+
3
x
]
0
√
3
=
2
[
−
3
√
3
3
+
3
√
3
]
=
2
[
−
√
3
+
3
√
3
]
=
4
√
3
sq units
© examsnet.com
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