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KEAM 2017 Math Paper
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© examsnet.com
Question : 30
Total: 120
1
∫
−
1
max
{
x
,
x
2
}
dx
is equal to
3/4
1/4
1/2
1
0
Validate
Solution:
Let
I
=
1
∫
−
1
max
{
x
,
x
3
}
d
x
=
0
∫
−
1
max
{
x
,
x
3
}
d
x
+
1
∫
0
max
{
x
,
x
3
}
d
x
=
0
∫
−
1
x
3
d
x
+
1
∫
0
x
d
x
=
[
x
4
4
]
−
1
0
+
[
x
2
2
]
0
1
=
[
0
−
(
1
4
)
]
+
[
1
2
−
0
]
=
−
1
4
+
1
2
=
1
4
© examsnet.com
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